Calculus
Got a midterm worksheet. Realized how confused I am.
Here are some questions:
lim x^3 + 12x^2 - 5x/5x
x->0
Find the indicated limit:
lim 11x/absolute value x
x->0+
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Answers
Answer: The limit is 11 as x approaches 0 from the positive side. Since the absolute value of x is always positive, the denominator of the fraction is always positive. This means that the limit of 11x/absolute value x as x approaches 0 from the positive side is equal to 11x/x, which simplifies to 11.
