calculus
find one point on the graph of y= x+2cosx such that the tanget is horizontal
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The point we are looking for is when the derivative of the function (the tangent line) is equal to zero. The derivative of the function is y' = 1 - 2sinx. Setting y' = 0 will give us 1 - 2sinx = 0, which is equivalent to sinx = 1/2. This means that x = pi/6. Thus, our point is (pi/6, x+2cosx) where x+2cosx = x+2cos(pi/6).
