Calculus
Find the volume of the solid obtained by rotating the region bounded by the curves about the line x=-3, y=x^2, x=y^2. I keep getting the wrong answer!! Please hellpp!! =(
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Answers
The region we wish to rotate is the triangular region V = \pi \int_{-1}^{1} (x^2)^2 - (y^2)^2 \,dy V = \pi \int_{-1}^1 (x^4-y^4) \, dy V = \pi \left [ \frac{x^5}{5} -\frac{y^5}{5} \right]_{-1}^1 V = \pi \left (\frac{1}{5} - \frac{(-1)^5}{5} \right ) V = \frac{2\pi}{5}
