Calculus

Suppose f(x)= e^(-1/x). Graph this function in the window -5(

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The graph of the given equation is shown below: ![graph of the given equation](graph.png) The tangent line to y=f(x) when x=2 is given by equation, y= 0.135*(x-2) + 6.047 The graph has two horizontal asymptotes, x=0 and x=+∞. The asymptote x=0 indicates that the function approaches a negative infinity at x=0, while the asymptote x=+∞ represents that the function approaches a positive infinity at x=+∞. The graph does not have any vertical asymptotes. The graph does not have any inflection points either. This is because the function is monotonically decreasing.

Answered by Jeffrey Davies

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