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. The hemophilia gene is located 12 map units from the red-green colorblindness gene on the X chromosome. Red-green colorblindness is recessive to normal color vision. A woman with normal blood clotting and normal color vision, but whose father was a hemophiliac and whose mother was red-green colorblind, marries a man who is not a hemophiliac and is not colorblind. What percent of their children will be colorblind and have hemophilia? Show your work and warrant your claim

Answers

Since both red-green colorblindness and hemophilia are recessive traits, in order for an individual to be colorblind and have hemophilia they must receive two recessive alleles from their parents, one from their mother and one from their father. The mother is a carrier of the red-green colorblindness gene, and the father does not carry the hemophilia gene. Since the mother is a carrier for the recessive red-green colorblindness gene and the father does not carry the hemophilia gene, their children would have a 25% chance of being colorblind and a 0% chance of having hemophilia. Therefore, the percent of the couple's children who would be both colorblind and have hemophilia would be 0%. Warrant: The fact that the mother is a carrier for the recessive red-green colorblindness gene, and the father does not carry the hemophilia gene, mathematically supports the conclusion that the percent of their children who will both be colorblind and have hemophilia is 0%.

Answered by ecraig

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