algebra
wright the equation of a line that is perpendicular to the given line and that passes through the given point
y-4=5/2 (x+3);(-7,8)
y-8=-2/5 (x-7)
y-8=2/5(x-7)*
y-8=-2/5(x+7)
y-8=2/5(x+7)
i’m not sure please help thank you:-)
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Answers
The equation of a line perpendicular to the given line is y-4 = -2/5(x+3). This line passes through the given point (-7, 8), so the equation of the perpendicular line is y-8 = -2/5(x+7).
