algebra
the length of a rectangle is twice the width. The area is 200yd^2. Find the length and the width.
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Let L be the length of the rectangle and W be the width. Since the length is twice the width, we can express this as L = 2W. We can use this equation to solve for the width, to obtain: W = L/2 = 200/2 = 100 yd. Once we know the width, we can use the original equation to solve for the length, to obtain: L = 2W = 2(100) = 200 yd. Therefore, the length of the rectangle is 200 yd and the width is 100 yd.
