Algebra II

How to solve Log (9x+5) - Log ((x^2)-1) = 1/2 16 16 (The 16 is from the logarithmic function : b) (y=log x) b Could anyone post the answer to this?

Answers

The answer to this is x = 4. In order to solve for x, you need to apply the following steps: 1. Rearrange the equation so that all the terms with logarithms are on the left side and the constant (1/2) is on the right side. 2. Divide both sides by the logarithmic base (here, 16) to isolate the variable. 3. Set the left side equal to zero, and solve for the variable. In this case, the equation looks like this: Log (9x+5) - Log ((x^2)-1) = 1/2 = 16 Rearrange the equation: Log (9x+5) - Log ((x^2)-1) - 1/2 = 0 Divide both sides by 16: (Log (9x+5) - Log ((x^2)-1) - 1/2) / 16 = 0 Set the left side equal to zero and simplify: Log (9x+5) - Log ((x^2)-1) = 1/2 Log (9x+5) = Log ((x^2)-1) + 1/2 9x + 5 =

Answered by john25

We have mentors from

Contact support