Algebra 1
complete.
6t to the 2nd power - 23t + 20=(3t - 4)(2t - .....)
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The expression 6t^2 - 23t + 20 can be factored as (3t - 4)(2t - 5). This follows from the factoring by grouping method. In this method, you group the terms in pairs and find two numbers whose product is equal to the constant term (20) and whose sum is equal to the coefficient of the middle term (-23). In this case, these numbers are 4 and 5, which gives us the factors (3t - 4) and (2t - 5).
