algebra 1
how do you factor 16x^4 - 40x^2 + 9 I don't understand how the factoring should go. When I think of a way to factor it it doesn't turn out right.
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16x4 - 40x2 + 9 The first step is to recognize that the given expression is a difference of squares. We can express this as (4x2 - 3)(4x2 + 3). Therefore: 16x4 - 40x2 + 9 = (4x2 - 3)(4x2 + 3) = (2x - 3)(2x + 3)(2x - 3)(2x + 3) = (2x - 3)2(2x + 3)2
