The energies of activation for forward and reverse reactions for A2 + B2 ⇋ 2AB are 180kJ mol^–1 and 200kJ mol^–1 respectively.

The energies of activation for forward and reverse reactions for A2 + B2 ⇋ 2AB are 180kJ mol–1 and 200kJ mol–1 respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by 100kJ mol–1. The enthalpy change of the reaction (A2 + B2 → 2AB) in the presence of a catalyst will be (in kJ mol–1 )(a) 20 (b) 300(c) 120 (d) 280.

Answers



The enthalpy change of the reaction (A2 + B2 → 2AB) in the presence of a catalyst will be 120 kJ/mol-1. This is because the presence of a catalyst will lower the activation energy of both (forward and reverse) reactions by 100 kJ/mol-1. Thus, the forward and reverse reaction activation energies will become 80 kJ/mol-1 and 100 kJ/mol-1 respectively. Since the net enthalpy change for a reaction is the difference between the forward and reverse reaction activation energies, the enthalpy change for the reaction (A2 + B2 → 2AB) will be 80 kJ/mol-1 - 100 kJ/mol-1 = -20 kJ/mol-1 (or 120 kJ/mol-1 for the reverse reaction). Thus, the correct answer is (c) 120 kJ/mol-1.

Answered by Jenna Phelps

Correct option (a) 20  Explanation:

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Answered by Melissa Nguyen

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