v(y)=v with letter y below normal line. "Explain why you can use the formula v(y)=g(t/2) to calculate the initial vertical velocity." My teacher claimed he explained the answer to this, but I didn't catch it. I would appreciate any help I get. THANKS!!!


The formula v(y)=g(t/2) is derived from the kinematic equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity, and t is the time elapsed. By rearranging the equation, we get u = v - at, where u is the initial velocity. In a free-falling motion, the acceleration due to gravity (a) is constant, so if we know the final velocity (v) and the time elapsed (t), we can calculate the initial velocity (u). In this case, v = g(t/2), because the calculated initial velocity is half of the potential velocity (which is equal to the acceleration due to gravity).

Answered by Ronald Brown

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