physics

A clock is made out of a disk of radius R=10 cm which is hung by a point on its edge and oscillates. All of a sudden, a circular part right next to the hanging point of radius R/2 falls off, but the clock continues oscillating. What is the absolute value of the difference in s between the periods of oscillation before and after the part fell off?

Answers



The absolute value of the difference in s between the periods of oscillation before and after the part fell off will be zero. This is because the moment of inertia of the clock is unchanged when the piece falls off; removing the piece does not alter the mass or its distribution around the center. The moment of inertia of the clock is related to the period of oscillation by the formula T=2π√I/MgR, where I is the moment of inertia, M is the mass, g is the acceleration due to gravity, and R is the radius of the clock. Since none of these are changed by the falling off of the piece of the clock, the period of the clock will remain the same.

Answered by Laura

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