physics
The initial speed of a cannonball is 520 m/s.
The acceleration of gravity is 9.8 m/s
2
. The
cannon and target are at the same elevation.
If the ball is to strike a target that is at a
horizontal distance of 2.7 km from the cannon,
what is the minimum time of flight for the
ball?
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Answers
The minimum time of flight for the ball is 27.7 seconds. This is calculated by using the equation for range, which is: R = VoT + (1/2)aT^2. In this equation, Vo is initial velocity, a is acceleration, and T is time of flight. After plugging in the initial velocity (520 m/s) and acceleration (9.8 m/s2), we can solve for the time of flight (T). This gives us a minimum time of 27.7 seconds.
