Intermidiate algebra

a woman ivests in two bank accounts, one with a 3% percent interest and the other paying 9% simple interest per year.She puts twice as much in the lower account. Her annual interest is 7110. How much did she invest in each account?

Answers



She invested $4,400 in the lower account that paid 3% interest ($4,400 x 0.03 = $132) and $8,800 in the higher account that paid 9% interest ($8,800 x 0.09 = $792). Her total annual interest was $910 ($132 + $792 = $910).

Answered by Donna

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