college physics

A 0.25 kg skeet (clay target) is fired at an angle of 30 degrees to the horizon with a speed of 25 m/s. When it reaches the maximum height, it is hit from below by a 15 g pellet travelling upward at a speed of 200 m/s. The pellet is embedded in the skeet. (a) How much higher did the skeet go up? (b) How much extra distance does the skeet travel because of the collision? the image is here: img85.imageshack.us/img85/905/physicsx.jpg

Answers

(a) The skeet will go up a distance of 63.3 cm. (b) The extra distance travelled by the skeet due to the collision is 0.75 m. The initial velocity of the skeet was 25 m/s at an angle of 30 degrees to the horizon, so the vertical and horizontal components of the initial velocity were 11.18 and 21.21 m/s, respectively. This means that without the collision, the skeet would have travelled 6.36 m horizontally and 4.66 m vertically. The collision, however, adds 0.75 m to the total distance traversed. Therefore, the total distance travelled by the skeet is 7.11 m.

Answered by Albert

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